Implementation-matching example: 15 ft by 15 ft at 2 in depth
Use the page's Paver Patio preset values as a transparent arithmetic example: a 15 ft by 15 ft rectangle, 2 in depth, 100 lb per cu ft entered density, and 10% allowance. The code calculates:
- Base volume: 15 × 15 × (2 ÷ 12) = 37.50 cu ft.
- Adjusted volume: 37.50 × 1.10 = 41.25 cu ft.
- Cubic yards: 41.25 ÷ 27 = 1.5278 cu yd.
- Weight: 41.25 × 100 = 4,125 lb.
- Short tons: 4,125 ÷ 2,000 = 2.0625 short tons.
- Fixed-load cross-check: 2.0625 ÷ 14 = 0.1473 of the page's 14-ton convention.
The displayed values round to 1.53 cu yd, 2.06 short tons, and 0.15 loads. This is an implementation-matching example, not a product depth recommendation, a paver installation detail, or a supplier delivery order.